8x^2-10x-30=0

Solution for 8x^2-10x-30=0 equation:

8x^2-10x-30=0

a = 8; b = -10; c = -30;
Δ = b2-4ac
Δ = -102-4·8·(-30)
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{265}}{2*8}=\frac{10-2\sqrt{265}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{265}}{2*8}=\frac{10+2\sqrt{265}}{16}
$